$Methyl$ propanoate on hydrolysis with dil $NaOH$ forms a salt that on further acidification with conc. $HCl$ forms:

  • A
    $CH_3COOH$
  • B
    $HCOOC_2H_5$
  • C
    $CH_3CH_2COOH$
  • D
    $CH_3COOC_2H_5$

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