H_{2} molecule is more stable than Li_{2} mol | vedclass

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(D) The electronic configuration of $H_{2}$ is $(\sigma_{1s})^2$,giving a bond order of $\frac{2-0}{2} = 1$.The electronic configuration of $Li_{2}$ i

Vedclass · Accepted Answer

In $Li_{2}$ molecule,outer $\sigma_{2s}$ molecular orbitals are shielded by the inner electrons.

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(D) The electronic configuration of $H_{2}$ is $(\sigma_{1s})^2$,giving a bond order of $\frac{2-0}{2} = 1$.The electronic configuration of $Li_{2}$ is $(\sigma_{1s})^2, (\sigma_{1s}^*)^2, (\sigma_{2s})^2$,giving a bond order of $\frac{4-2}{2} = 1$.However,in $Li_{2}$,the presence of inner $(\sigma_{1s})^2$ and $(\sigma_{1s}^*)^2$ electrons effectively shields the valence $\sigma_{2s}$ electrons from the nucleus,reducing the effective nuclear charge experienced by the bonding electrons and making the bond weaker compared to $H_{2}$.

$H_{2}$ molecule is more stable than $Li_{2}$ molecule,because

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