$60 \ g$ of $CH_3COOH$ is dissolved in $1 \ dm^3$ of solvent. What is the molality of the solution (in $m$)? (Density $= 1.25 \ g / cm^3$)

$A$ solution contains $1 \ mole$ of water and $4 \ mole$ of ethanol. The mole fraction of water and ethanol will be

Calculate the molality of $1 \ L$ solution of $93 \ \%$ $H_2SO_4$ (weight/volume). The density of the solution is $1.84 \ g/mL$.

What is the difference between molality and molarity?

The molarity of pure water at $4\,^{\circ}C$ is ............... $M$.

The molality of a $10\%\ (v/v)$ solution of di-bromine in $CCl_4$ (carbon tetrachloride) is $x$. $x = ...... \times 10^{-2}\ m$. (Nearest integer)
[Given : molar mass of $Br_2 = 160\ g\ mol^{-1}$
atomic mass of $C = 12\ g\ mol^{-1}$
atomic mass of $Cl = 35.5\ g\ mol^{-1}$
density of dibromine $= 3.2\ g\ cm^{-3}$
density of $CCl_4 = 1.6\ g\ cm^{-3}$]