(B) The formula for osmotic pressure is $\pi = \frac{W_2 RT}{M_2 V}$.Rearranging for molar mass $M_2$,we get $M_2 = \frac{W_2 RT}{\pi V}$.Substituting

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(B) The formula for osmotic pressure is $\pi = \frac{W_2 RT}{M_2 V}$.Rearranging for molar mass $M_2$,we get $M_2 = \frac{W_2 RT}{\pi V}$.Substituting the given values: $W_2 = 8 \ g$,$R = 0.082 \ atm \ dm^3 \ K^{-1} \ mol^{-1}$,$T = 300 \ K$,$\pi = 0.6 \ atm$,and $V = 2 \ dm^3$.$M_2 = \frac{8 \times 0.082 \times 300}{0.6 \times 2} \ g \ mol^{-1}$.$M_2 = \frac{196.8}{1.2} \ g \ mol^{-1} = 164 \ g \ mol^{-1}$.

Class 12 Chemistry Solutions Osmosis and Osmotic pressure of the solution

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$A$ solution of $8 \ g$ of a certain organic compound in $2 \ dm^3$ of water develops an osmotic pressure of $0.6 \ atm$ at $300 \ K$. Calculate the molar mass of the compound. $\left[R = 0.082 \ atm \ dm^3 \ K^{-1} \ mol^{-1}\right]$

MHT CET 2023 All MHT CET

A
$148 \ g \ mol^{-1}$
B
$164 \ g \ mol^{-1}$
C
$172 \ g \ mol^{-1}$
D
$180 \ g \ mol^{-1}$

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If the osmotic pressure of cane sugar solution is $2.46 \ atm$ at $27^{\circ} C$,then what is the concentration (in $mol \ L^{-1}$) of the solution $(R=0.0821 \ L \ atm \ mol^{-1} \ K^{-1})$?

MediumAP EAMCET 2023

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MediumAIPMT 2006

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At a certain temperature,the osmotic pressure of a $0.25 \, M$ solution of a non-electrolyte is $\pi \, bar$. What will be the osmotic pressure of a $0.125 \, M \, Ba(NO_3)_2$ solution at the same temperature?

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The plot of osmotic pressure $(\Pi)$ vs concentration $\left(mol \ L^{-1}\right)$ for a solution gives a straight line with slope $25.73 \ L \ bar \ mol^{-1}$. The temperature at which the osmotic pressure measurement is done is
(Use $R=0.083 \ L \ bar \ mol^{-1} \ K^{-1}$) (in $^{\circ} C$)

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$A$ solution of $8 \ g$ of a certain organic compound in $2 \ dm^3$ of water develops an osmotic pressure of $0.6 \ atm$ at $300 \ K$. Calculate the molar mass of the compound. $\left[R = 0.082 \ atm \ dm^3 \ K^{-1} \ mol^{-1}\right]$

Similar Questions

$90 \, g$ of $CH_3COOH$ $(i = 0.5)$ is dissolved in $110 \, g$ of benzene. What will be its osmotic pressure at $300 \, K$ if the density of the solution is $1.2 \, g/mL$? (Answer in $atm$)

If the osmotic pressure of cane sugar solution is $2.46 \ atm$ at $27^{\circ} C$,then what is the concentration (in $mol \ L^{-1}$) of the solution $(R=0.0821 \ L \ atm \ mol^{-1} \ K^{-1})$?

$A$ solution containing $10 \ g$ per $dm^3$ of urea (molecular mass $= 60 \ g \ mol^{-1}$) is isotonic with a $5 \%$ solution of a non-volatile solute. The molecular mass of this non-volatile solute is ........ $g \ mol^{-1}$.

At a certain temperature,the osmotic pressure of a $0.25 \, M$ solution of a non-electrolyte is $\pi \, bar$. What will be the osmotic pressure of a $0.125 \, M \, Ba(NO_3)_2$ solution at the same temperature?

The plot of osmotic pressure $(\Pi)$ vs concentration $\left(mol \ L^{-1}\right)$ for a solution gives a straight line with slope $25.73 \ L \ bar \ mol^{-1}$. The temperature at which the osmotic pressure measurement is done is(Use $R=0.083 \ L \ bar \ mol^{-1} \ K^{-1}$) (in $^{\circ} C$)

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The plot of osmotic pressure $(\Pi)$ vs concentration $\left(mol \ L^{-1}\right)$ for a solution gives a straight line with slope $25.73 \ L \ bar \ mol^{-1}$. The temperature at which the osmotic pressure measurement is done is
(Use $R=0.083 \ L \ bar \ mol^{-1} \ K^{-1}$) (in $^{\circ} C$)