$A$ sample of calcium carbonate has the following percentage composition: $Ca = 40 \%$,$C = 12 \%$,and $O = 48 \%$. According to the law of definite proportion,the weight of calcium in $4 \ g$ of a sample of calcium carbonate from another source will be (atomic weights: $Ca = 40, C = 12, O = 16$).
- A$1.6 \times 10^{-2} \ g$
- B$1.6 \ g$
- C$0.1 \ g$
- D$0.2 \ g$
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From the given information, select the suitable law of chemical combination: Cupric Carbonate % of $Cu$ % of $C$ % of $O$ Natural sample $51.35$ $9.74$ $38.91$ Synthetic sample $51.35$ $9.74$ $38.91$
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| Natural sample | $51.35$ | $9.74$ | $38.91$ |
| Synthetic sample | $51.35$ | $9.74$ | $38.91$ |
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