A gas absorbs 150 J of heat and expands by 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Heat absorbed $(q)$ = $+150 \ J$ (since heat is absorbed by the system). External pressure $(P_{ext})$ = $2 	imes 10^5 \ N \ m^{-2}$. Chan

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(B) Given: Heat absorbed $(q)$ = $+150 \ J$ (since heat is absorbed by the system). External pressure $(P_{ext})$ = $2 	imes 10^5 \ N \ m^{-2}$. Change in volume $(\Delta V)$ = $300 \ cm^3 = 300 	imes 10^{-6} \ m^3 = 3 	imes 10^{-4} \ m^3$. Work done $(W)$ = $-P_{ext} 	imes \Delta V$. $W = -(2 	imes 10^5 \ N \ m^{-2}) 	imes (3 	imes 10^{-4} \ m^3) = -60 \ J$. According to the first law of thermodynamics: $\Delta U = q + W$. $\Delta U = 150 \ J + (-60 \ J) = 90 \ J$.

$A$ gas absorbs $150 \ J$ of heat and expands by $300 \ cm^3$ against a constant external pressure of $2 \times 10^5 \ N \ m^{-2}$. What is the change in internal energy $(\Delta U)$ of the system (in $J$)?

Similar Questions

Which of the following expressions represents the first law of thermodynamics?

Three moles of an ideal gas expand reversibly under isothermal conditions from $2 \, L$ to $20 \, L$ at $300 \, K$. The amount of heat change (in $kJ / mol$) in the process is:

During compression of a spring,the work done is $10 \ kJ$ and $2 \ kJ$ escaped to the surroundings as heat. The change in internal energy,$\Delta U$ (in $kJ$),is

$A$ gas absorbs $200 \ J$ of heat and expands by $500 \ cm^3$ against a constant external pressure of $2 \times 10^5 \ N \ m^{-2}$. What is the change in internal energy (in $J$)?

Which one of the following is applicable for an adiabatic expansion of an ideal gas?

Vedclass Test Series

Exam Paper Generator

Online Exam Module