$m$ men and $n$ women are to be seated in a row so that no two women sit together. If $m > n$,then the number of ways in which they can be seated is

  • A
    $\frac{m! (m + 1)!}{(m - n + 1)!}$
  • B
    $\frac{m! (m - 1)!}{(m - n + 1)!}$
  • C
    $\frac{(m - 1)! (m + 1)!}{(m - n + 1)!}$
  • D
    None of these

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