21 friends were invited for a party. Two roun | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: Select $12$ friends out of $21$ to sit at the first table. The number of ways is $\binom{21}{12}$.Step $2$: The number of ways to arrang

Vedclass · Accepted Answer

$\binom{21}{12} 	imes 11! 	imes 8!$

Vedclass · Answer

(D) Step $1$: Select $12$ friends out of $21$ to sit at the first table. The number of ways is $\binom{21}{12}$.Step $2$: The number of ways to arrange $12$ friends at a round table is $(12-1)! = 11!$.Step $3$: The remaining $9$ friends are to be seated at the second round table. The number of ways to arrange them is $(9-1)! = 8!$.Step $4$: The total number of ways is $\binom{21}{12} 	imes 11! 	imes 8! = \frac{21!}{12!9!} 	imes 11! 	imes 8! = \frac{21!}{12 	imes 9} = \frac{21!}{108}$.

$21$ friends were invited for a party. Two round tables can accommodate $12$ and $9$ friends respectively. The number of ways of the seating arrangements of friends is:

Similar Questions

If $11$ members of a committee sit at a round table so that the President and Secretary always sit together,then the number of arrangements is

The number of ways in which $5$ boys and $4$ girls can sit around a circular table such that no two girls sit together is:

Let $m$ denote the number of ways in which $5$ boys and $5$ girls can be arranged in a line alternately,and $n$ denote the number of ways in which $5$ boys and $5$ girls can be arranged in a circle so that no two boys are together. If $m = kn$,then the value of $k$ is

The number of ways of arranging $8$ men and $4$ women around a circular table such that no two women can sit together is

Vedclass Test Series

Exam Paper Generator

Online Exam Module