Medium
$A$ $20 \Omega$ resistance,$10 \text{ mH}$ inductance coil,and $15 \mu \text{F}$ capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination,the circuit resonates. If the resistance is made $1/3$ rd of its original value,the resonant frequency:
- Aremains unchanged.
- Bis doubled.
- Cis quadrupled.
- Dis halved.
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Similar Questions
$A$ series $LCR$ circuit with $L = \frac{100}{\pi} \text{ mH}$,$C = \frac{10^{-3}}{\pi} \text{ F}$,and $R = 10 \ \Omega$ is connected across an $AC$ source of $220 \text{ V}, 50 \text{ Hz}$ supply. The power factor of the circuit would be . . . . . . .
DifficultJEE MAIN 2024
View Solution$A$ series $LCR$ circuit is connected to an ac voltage source. When $L$ is removed from the circuit,the phase difference between current and voltage is $\frac{\pi}{3}$. If instead $C$ is removed from the circuit,the phase difference is again $\frac{\pi}{3}$ between current and voltage. The power factor of the circuit is:
MediumNEET 2020
View SolutionThe power in an $AC$ circuit is given by $P = E_{rms}I_{rms} \cos \phi$. The value of $\cos \phi$ in a series $LCR$ circuit at resonance is:
Medium
View SolutionThe $LC$ parallel resonant circuit:
The reading of the ammeter in the following circuit is (in $A$)
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