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(B) When the capacitor is charged and then disconnected from the battery,the charge $Q$ on the plates remains constant because there is no path for th

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the voltage across the capacitor increases

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(B) When the capacitor is charged and then disconnected from the battery,the charge $Q$ on the plates remains constant because there is no path for the charge to flow.The capacitance $C$ of a parallel plate capacitor is given by $C = \frac{A \varepsilon_0}{d}$.When the plates are moved further apart,the distance $d$ increases,which causes the capacitance $C$ to decrease.Since the charge $Q$ is constant and $Q = CV$,the voltage $V = \frac{Q}{C}$ must increase as $C$ decreases.Therefore,the voltage across the capacitor increases.

$A$ parallel plate capacitor is charged and then disconnected from the charging battery. If the plates are now moved further apart by pulling them by means of insulating handles,then

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