$A$ capacitor of capacity $C_1$ is charged to potential $V_1$ and then disconnected. An uncharged capacitor of capacity $C_2$ is connected in parallel with $C_1$. The resultant potential $V_2$ is

  • A
    $\frac{V_1 C_2}{C_1}$
  • B
    $\frac{C_2}{C_1+C_2}$
  • C
    $\frac{C_1 V_1}{C_2}$
  • D
    $\frac{C_1 V_1}{C_1+C_2}$

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Consider the situation shown in the figure. Capacitor $A$ has a charge $q$ on it,whereas $B$ is uncharged. The charge appearing on capacitor $B$ a long time after the switch $S$ is closed is

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