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(C) In a parallel combination,the potential difference $V$ across each capacitor is the same.Given $V = 5 	ext{ V}$,$C_1 = 2C$,and $C_2 = C$.Charge s

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$\frac{5}{2}$

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(C) In a parallel combination,the potential difference $V$ across each capacitor is the same.Given $V = 5 	ext{ V}$,$C_1 = 2C$,and $C_2 = C$.Charge stored in a capacitor is given by $Q = CV$.$Q_1 = C_1 V = (2C)(5) = 10C 	ext{ C}$.$Q_2 = C_2 V = (C)(5) = 5C 	ext{ C}$.Energy stored in a capacitor is given by $E = \frac{1}{2}CV^2$.$E_1 = \frac{1}{2} C_1 V^2 = \frac{1}{2} (2C) (5)^2 = 25C 	ext{ J}$.$E_2 = \frac{1}{2} C_2 V^2 = \frac{1}{2} (C) (5)^2 = 12.5C 	ext{ J}$.Now,calculate the ratio $\frac{E_1-E_2}{Q_1-Q_2}$:$\frac{E_1-E_2}{Q_1-Q_2} = \frac{25C - 12.5C}{10C - 5C} = \frac{12.5C}{5C} = \frac{12.5}{5} = 2.5 = \frac{5}{2}$.

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