A ball kept at 20 ,m height falls freely in a | vedclass

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(A) Given: Height $h = 20 \,m$, acceleration due to gravity $g = 10 \,m/s^2$, and coefficient of restitution $e = 0.4$.First, calculate the velocity $

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$8$

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(A) Given: Height $h = 20 \,m$, acceleration due to gravity $g = 10 \,m/s^2$, and coefficient of restitution $e = 0.4$.First, calculate the velocity $v$ of the ball just before it hits the ground using the equation of motion $v^2 = u^2 + 2gh$ (where initial velocity $u = 0$):$v = \sqrt{2gh} = \sqrt{2 	imes 10 	imes 20} = \sqrt{400} = 20 \,m/s$.The coefficient of restitution $e$ is defined as the ratio of the velocity of separation (rebound velocity $v'$) to the velocity of approach (impact velocity $v$):$e = \frac{v'}{v}$.Therefore, the upward rebound velocity $v'$ is:$v' = e 	imes v = 0.4 	imes 20 = 8 \,m/s$.

$A$ ball kept at $20 \,m$ height falls freely in a downward direction vertically and hits the ground. The coefficient of restitution is $0.4$. After the first rebound, the upward velocity is $[g = 10 \,m/s^2]$. (in $\,m/s$)

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