$A$ moving coil galvanometer is converted into an ammeter, reading up to $0.04 \,A$ by connecting a shunt of resistance '$3r$' across it and then into an ammeter reading up to $0.8 \,A$, when a shunt of resistance '$r$' is connected across it. What is the maximum current which can be sent through this galvanometer if no shunt is used (in $\,A$)?

$A$ galvanometer with a resistance of $8 \, \Omega$ is connected to a shunt of $2 \, \Omega$. If the total current is $1 \, A$,how much current in $A$ passes through the shunt?

$A$ galvanometer of resistance $30 \Omega$ is connected to a battery of emf $2 \text{ V}$ with $1970 \Omega$ resistance in series. $A$ full-scale deflection of $20$ divisions is obtained in the galvanometer. To reduce the deflection to $10$ divisions,the total resistance in series required is: (in $\Omega$)

$A$ moving coil galvanometer allows a full-scale current of $10^{-4} \ A$. $A$ series resistance of $2 \ M\Omega$ is required to convert the above galvanometer into a voltmeter of range $0-5 \ V$. Therefore,the value of shunt resistance required to convert the above galvanometer into an ammeter of range $0-10 \ mA$ is .... $\Omega$.

$A$ galvanometer,having a resistance of $50 \Omega$,gives a full scale deflection for a current of $0.05 \text{ A}$. The length in metre of a resistance wire of area of cross-section $2.97 \times 10^{-2} \text{ cm}^2$ that can be used to convert the galvanometer into an ammeter which can read a maximum of $5 \text{ A}$ current is: (Specific resistance of the wire $= 5 \times 10^{-7} \Omega\text{-m}$)

$A$ $36 \,\Omega$ galvanometer is shunted by a resistance of $4 \,\Omega$. The percentage of the total current that passes through the galvanometer is (in $\%$)