A 220 V input is supplied to a transformer. T | vedclass

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(B) Given,input voltage supplied to the transformer,$V_1 = 220 V$.Output voltage,$V_2 = 440 V$.Output current,$i_2 = 2.0 A$.The efficiency (ratio of o

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$5.0$

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(B) Given,input voltage supplied to the transformer,$V_1 = 220 V$.Output voltage,$V_2 = 440 V$.Output current,$i_2 = 2.0 A$.The efficiency (ratio of output power to input power) is given by $\eta = \frac{P_2}{P_1} = 0.8$.We know that $P_2 = V_2 	imes i_2$ and $P_1 = V_1 	imes i_1$.Substituting the values: $\frac{V_2 	imes i_2}{V_1 	imes i_1} = 0.8$.$\frac{440 	imes 2.0}{220 	imes i_1} = 0.8$.$2 	imes 2.0 = 0.8 	imes i_1$.$4.0 = 0.8 	imes i_1$.$i_1 = \frac{4.0}{0.8} = 5.0 A$.Therefore,the current drawn by the primary winding is $5.0 A$.

$A$ $220 V$ input is supplied to a transformer. The output circuit draws a current of $2.0 A$ at $440 V$. If the ratio of output to input power is $0.8$,then the current drawn by the primary winding is: (in $A$)

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