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(C) According to Faraday's law of induction,the induced electromotive force $(e)$ is given by $e = -\frac{\Delta \phi}{\Delta t}$.Using Ohm's law,the

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the total change in magnetic flux and $R$.

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(C) According to Faraday's law of induction,the induced electromotive force $(e)$ is given by $e = -\frac{\Delta \phi}{\Delta t}$.Using Ohm's law,the induced current $(i)$ is $i = \frac{e}{R} = \frac{1}{R} \cdot \frac{\Delta \phi}{\Delta t}$.Since current is the rate of flow of charge,we have $i = \frac{\Delta q}{\Delta t}$.Equating the two expressions for current: $\frac{\Delta q}{\Delta t} = \frac{1}{R} \cdot \frac{\Delta \phi}{\Delta t}$.Therefore,the total induced charge is $\Delta q = \frac{\Delta \phi}{R}$.This shows that the total induced charge depends only on the total change in magnetic flux $(\Delta \phi)$ and the resistance $(R)$.

$A$ conducting loop of resistance $R$ is moved into a magnetic field. The total induced charge depends upon:

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