A magnetic field 4 times 10^{-2} , T acts at | vedclass

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(C) Given:Magnetic field $B = 4 	imes 10^{-2} \, T$Area $A = 100 \, cm^2 = 100 	imes 10^{-4} \, m^2 = 10^{-2} \, m^2$Number of turns $N = 50$Induced

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$0.2$ second

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(C) Given:Magnetic field $B = 4 	imes 10^{-2} \, T$Area $A = 100 \, cm^2 = 100 	imes 10^{-4} \, m^2 = 10^{-2} \, m^2$Number of turns $N = 50$Induced e.m.f. $\varepsilon = 0.1 \, V$The magnetic flux $\phi$ through the coil is $\phi = B \cdot A \cdot \cos(0^\circ) = B \cdot A$.Initial flux $\phi_i = B \cdot A = (4 	imes 10^{-2} \, T) 	imes (10^{-2} \, m^2) = 4 	imes 10^{-4} \, Wb$.Final flux $\phi_f = 0$ (as it is removed from the field).The magnitude of average induced e.m.f. is given by Faraday's Law:$|\varepsilon| = N \cdot \frac{|\Delta \phi|}{t} = N \cdot \frac{|\phi_f - \phi_i|}{t}$$0.1 = 50 	imes \frac{|0 - 4 	imes 10^{-4}|}{t}$$0.1 = \frac{50 	imes 4 	imes 10^{-4}}{t}$$0.1 = \frac{200 	imes 10^{-4}}{t} = \frac{0.02}{t}$$t = \frac{0.02}{0.1} = 0.2 \, s$.Therefore, the value of '$t$' is $0.2 \, s$.

$A$ magnetic field $4 \times 10^{-2} \, T$ acts at right angles to a coil of area $100 \, cm^2$ with $50$ turns. The average e.m.f. induced in the coil is $0.1 \, V$, when it is removed from the field in time '$t$'. The value of '$t$' is

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