A coil has an area 0.06 m^2 and it has 600 t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The induced electromotive force (e.m.f) is given by Faraday's law of induction: $e = -N \frac{d\phi}{dt} = -N \frac{\phi_2 - \phi_1}{t}$.Given: Ar

Vedclass · Accepted Answer

$9 	imes 10^{-3} \ V$

Vedclass · Answer

(D) The induced electromotive force (e.m.f) is given by Faraday's law of induction: $e = -N \frac{d\phi}{dt} = -N \frac{\phi_2 - \phi_1}{t}$.Given: Area $A = 0.06 \ m^2$,Number of turns $N = 600$,Magnetic field $B = 5 	imes 10^{-5} \ Wb/m^2$,Time $t = 0.2 \ s$.The magnetic flux is $\phi = BA \cos 	heta$.Initially,the coil is perpendicular to the magnetic field,so $	heta_1 = 0^{\circ}$ and $\phi_1 = BA \cos 0^{\circ} = BA$.After rotating by $90^{\circ}$,the coil is parallel to the magnetic field,so $	heta_2 = 90^{\circ}$ and $\phi_2 = BA \cos 90^{\circ} = 0$.The magnitude of the average induced e.m.f is:$|e| = N \frac{|\phi_2 - \phi_1|}{t} = N \frac{|0 - BA|}{t} = \frac{NBA}{t}$.Substituting the values:$|e| = \frac{600 	imes 5 	imes 10^{-5} 	imes 0.06}{0.2} = \frac{1.8 	imes 10^{-3}}{0.2} = 9 	imes 10^{-3} \ V$.

$A$ coil has an area $0.06 \ m^2$ and it has $600$ turns. After placing the coil in a magnetic field of strength $5 \times 10^{-5} \ Wb/m^2$,it is rotated through $90^{\circ}$ in $0.2 \ s$. The magnitude of average e.m.f induced in the coil is

Similar Questions

There is a uniform magnetic field directed perpendicular and into the plane of the paper. An irregular shaped conducting loop is slowly changing into a circular loop in the plane of the paper. Then

The working of a dynamo is based on the principle of

As shown in the figure,a bar magnet is moving towards a stationary coil with a constant speed $v$. The direction of the induced current in the coil as observed by the observer on the $R$.$H$.$S$. is . . . . . . .

The area of a coil is $A$. The coil is placed in a magnetic field which changes from $B_{0}$ to $4 B_{0}$ in time $t$. The magnitude of the induced e.m.f. in the coil will be:

The magnetic flux through a coil perpendicular to its plane and directed into the paper is varying according to the relation $\phi = 5t^2 + 10t + 5$ milliweber. The $e.m.f.$ induced in the loop after $5 \, s$ is ..... $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module