A coil of n turns and resistance R Omega is | vedclass

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(A) The total resistance of the circuit is $R_{total} = R + \frac{R}{2} = \frac{3R}{2}$.According to Faraday's law of electromagnetic induction,the ma

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$\frac{2 n(\phi_{1}-\phi_{2})}{3 R t}$

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(A) The total resistance of the circuit is $R_{total} = R + \frac{R}{2} = \frac{3R}{2}$.According to Faraday's law of electromagnetic induction,the magnitude of induced electromotive force $(EMF)$ is $e = n \frac{|\Delta \phi|}{\Delta t} = n \frac{|\phi_{1} - \phi_{2}|}{t}$.The induced current $i$ is given by $i = \frac{e}{R_{total}}$.Substituting the values,we get $i = \frac{n |\phi_{1} - \phi_{2}| / t}{3R/2} = \frac{2n |\phi_{1} - \phi_{2}|}{3Rt}$.Thus,the induced current is $\frac{2n(\phi_{1} - \phi_{2})}{3Rt}$.

$A$ coil of $n$ turns and resistance $R \ \Omega$ is connected in series with a resistance $R/2$. The combination is moved for time $t$ seconds through a magnetic flux change from $\phi_{1}$ to $\phi_{2}$. The induced current in the circuit is:

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