$A$ metal rod of length '$l$' rotates about one of its ends in a plane perpendicular to a magnetic field of induction '$B$'. If the e.m.f. induced between the ends of the rod is '$e$',then the number of revolutions made by the rod per second is

  • A
    $\frac{e}{B \pi l^2}$
  • B
    $\frac{e}{B \pi^2 l}$
  • C
    $\frac{B^2}{e \pi l}$
  • D
    $\frac{\pi l^2}{eB}$

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