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(C) Given that a constant force $F$ acts on mass $m_1$,the acceleration is $A_1 = \frac{F}{m_1}$,which implies $m_1 = \frac{F}{A_1}$.Similarly,for mas

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$\frac{A_1 A_2}{A_1 + A_2}$

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(C) Given that a constant force $F$ acts on mass $m_1$,the acceleration is $A_1 = \frac{F}{m_1}$,which implies $m_1 = \frac{F}{A_1}$.Similarly,for mass $m_2$,the acceleration is $A_2 = \frac{F}{m_2}$,which implies $m_2 = \frac{F}{A_2}$.When the same force $F$ acts on the combined mass $(m_1 + m_2)$,the acceleration $A$ is given by $A = \frac{F}{m_1 + m_2}$.Substituting the values of $m_1$ and $m_2$ into the equation:$A = \frac{F}{\frac{F}{A_1} + \frac{F}{A_2}}$$A = \frac{F}{F(\frac{1}{A_1} + \frac{1}{A_2})}$$A = \frac{1}{\frac{A_1 + A_2}{A_1 A_2}}$$A = \frac{A_1 A_2}{A_1 + A_2}$.

$A$ constant force $F$ acts on two different masses $m_1$ and $m_2$ independently and produces accelerations $A_1$ and $A_2$ respectively. When the same force $F$ acts on their combined mass $(m_1 + m_2)$,the acceleration $A$ produced is:

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