$A$ straight wire carrying current $I$ is bent into a semi-circular arc of radius $r$,as shown. The magnitude of the magnetic field at point $O$ due to the semi-circular arc is ($\mu_{0} =$ permeability of free space).
- A$\frac{\mu_{0} I}{4 r}$
- B$\frac{\mu_{0} I}{2 r}$
- C$\frac{\mu_{0} I}{r^{2}}$
- D$\frac{\mu_{0} I}{r}$
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