$A$ square loop of area $25 \, cm^2$ has a resistance of $10 \, \Omega$. The loop is placed in a uniform magnetic field of magnitude $40 \, T$. The plane of the loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in $1 \, s$ will be:

• A
  $2.5 \times 10^{-3} \, J$
• B
  $1.0 \times 10^{-3} \, J$
• C
  $1.0 \times 10^{-4} \, J$
• D
  $5 \times 10^{-3} \, J$