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Question

(D) According to Gauss's law,the total electric flux through a closed surface is $\frac{1}{\varepsilon_{0}}$ times the net charge enclosed by the surf

Vedclass · Accepted Answer

$\frac{q}{8 \varepsilon_{0}}$

Vedclass · Answer

(D) According to Gauss's law,the total electric flux through a closed surface is $\frac{1}{\varepsilon_{0}}$ times the net charge enclosed by the surface.When a charge $q$ is placed at the corner of a cube,it is shared equally by $8$ adjacent cubes to form a symmetric closed Gaussian surface.Therefore,the flux through one single cube is $\frac{1}{8}$ of the total flux produced by the charge $q$.Thus,the electric flux through the cube is $\phi = \frac{q}{8 \varepsilon_{0}}$.

$A$ charge $q$ is placed at the corner of a cube of side $a$. The electric flux through the cube is

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