$A$ straight wire of diameter $0.4 \,mm$ carrying a current of $2 \,A$ is replaced by another wire of $0.8 \,mm$ diameter carrying the same current. The magnetic field at distance $R$ from both the wires is $B_1$ and $B_2$ respectively. The relation between $B_1$ and $B_2$ is

  • A
    $B_1 = \frac{B_2}{2}$
  • B
    $B_1 = B_2$
  • C
    $B_1 = 2 \,B_2$
  • D
    $B_1 = \frac{B_2}{3}$

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