$A$ charge '$q$' moves with velocity '$\overrightarrow{v}$' through an electric field '$\overrightarrow{E}$' as well as a magnetic field '$\overrightarrow{B}$'. Then the force acting on it is:
- A$q(\overrightarrow{v} \times \overrightarrow{B})$
- B$q(\overrightarrow{B} \times \overrightarrow{v})$
- C$q(\overrightarrow{E} \times \overrightarrow{v})$
- D$q\overrightarrow{E} + q(\overrightarrow{v} \times \overrightarrow{B})$
Explore More
Similar Questions
What is the behavior of a charged particle moving in a region where the electric field $\vec{E}$ and magnetic field $\vec{B}$ are perpendicular to each other?
Easy
View SolutionIf $E$ and $B$ are the magnitudes of electric and magnetic fields respectively in some region of space, then the possibilities for which a charged particle may move in that space with a uniform velocity of magnitude $v$ are
$A$ charge $q$ moves in a region where both an electric field and a magnetic field exist. The total force on it is:
$A$ stream of charged particles enters a region with crossed electric and magnetic fields as shown in the figure below. On the other side is a screen with a hole that is right on the original path of the particles. Then,
MediumKVPY 2009
View SolutionWrite the Lorentz force equation.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo