$A$ bar magnet having length $5 \ cm$ and area of cross-section $4 \ cm^{2}$ has a magnetic moment of $2 \ Am^{2}$. If the magnetic susceptibility is $5 \times 10^{-6}$,the magnetic intensity will be:
- A$0.2 \times 10^{10} \ A/m$
- B$0.5 \times 10^{10} \ A/m$
- C$5 \times 10^{10} \ A/m$
- D$2 \times 10^{10} \ A/m$
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Similar Questions
$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, Am^{-1}$. As a result,a magnetic moment of $5 \, Am^2$ is produced in the rod. The value of magnetic induction will be.... $T$
Medium
View SolutionThe magnetic susceptibility of a paramagnetic substance at $-123^{\circ} C$ is $0.0060$. What will be its value at $-173^{\circ} C$?
Easy
View SolutionThe magnetic induction and the intensity of the magnetic field inside an iron core of an electromagnet are $1 \ Wb \ m^{-2}$ and $150 \ A \ m^{-1}$, respectively. The relative permeability of iron is $(\mu_0 = 4 \pi \times 10^{-7} \ H \ m^{-1})$.
The domain in a ferromagnetic material is in the form of a cube of side $2 \mu m$. The number of atoms in that domain is $9 \times 10^{10}$ and each atom has a dipole moment of $9 \times 10^{-24} A m^2$. The magnetization of the domain is (approximately):
If $M$ is the magnetisation induced in the material,$H$ is the magnetic field intensity,and $B$ is the net magnetic field inside the material,then the correct relation between them is $(\mu_0 = \text{permeability of free space})$
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