(A) The energy density $(u)$ of a stretched wire is given by the formula: $u = \frac{1}{2} \times Y \times (\text{strain})^{2}$.Given:Young's modulus

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(A) The energy density $(u)$ of a stretched wire is given by the formula: $u = \frac{1}{2} \times Y \times (\text{strain})^{2}$.Given:Young's modulus $(Y)$ = $1.6 \times 10^{12} \,N/m^{2}$.Strain = $2 \times 10^{-4}$.Substituting the values into the formula:$u = \frac{1}{2} \times (1.6 \times 10^{12}) \times (2 \times 10^{-4})^{2}$.$u = 0.5 \times 1.6 \times 10^{12} \times 4 \times 10^{-8}$.$u = 0.8 \times 4 \times 10^{12-8}$.$u = 3.2 \times 10^{4} \,J/m^{3}$.

Class 11 Physics Mechanical Properties of Solids Work Done in Stretching a Wire

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$A$ wire of Young's modulus $1.6 \times 10^{12} \,N/m^{2}$ is stretched by a force so as to produce a strain of $2 \times 10^{-4}$. The energy density of the wire is

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A
$3.2 \times 10^{4} \,J/m^{3}$
B
$3.2 \times 10^{8} \,J/m^{3}$
C
$1.6 \times 10^{3} \,J/m^{3}$
D
$6.4 \times 10^{3} \,J/m^{3}$

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$A$ wire of Young's modulus $1.6 \times 10^{12} \,N/m^{2}$ is stretched by a force so as to produce a strain of $2 \times 10^{-4}$. The energy density of the wire is

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