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(C) The frequency of a stretched string is given by the formula $n = \frac{1}{2L} \sqrt{\frac{T}{\mu}}$,where $L$ is the length,$T$ is the tension,and

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$6: 5$

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(C) The frequency of a stretched string is given by the formula $n = \frac{1}{2L} \sqrt{\frac{T}{\mu}}$,where $L$ is the length,$T$ is the tension,and $\mu$ is the mass per unit length.Initially,the frequency is $n_1 = \frac{1}{2L} \sqrt{\frac{T_1}{\mu}}$.When the tension is increased by $44\%$,the new tension $T_2$ becomes $T_2 = T_1 + 0.44T_1 = 1.44T_1$.The new frequency $n_2$ is given by $n_2 = \frac{1}{2L} \sqrt{\frac{1.44T_1}{\mu}}$.Taking the ratio of $n_2$ to $n_1$:$\frac{n_2}{n_1} = \frac{\frac{1}{2L} \sqrt{\frac{1.44T_1}{\mu}}}{\frac{1}{2L} \sqrt{\frac{T_1}{\mu}}} = \sqrt{\frac{1.44T_1}{T_1}} = \sqrt{1.44} = 1.2$.Converting $1.2$ to a fraction,we get $1.2 = \frac{12}{10} = \frac{6}{5}$.Thus,the ratio $n_2:n_1$ is $6:5$.

$A$ violin emits sound waves of frequency $n_1$ under tension $T$. When tension is increased by $44\%$,keeping the length and mass per unit length constant,the frequency of sound waves becomes $n_2$. The ratio of frequency $n_2$ to frequency $n_1$ is:

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