A pendulum clock is running fast. To correct | vedclass

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(C) The time period $T$ of a simple pendulum is given by the formula:$T = 2\pi \sqrt{\frac{\ell}{g}}$From this relation,we can see that $T \propto \sq

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increase the length of the pendulum

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(C) The time period $T$ of a simple pendulum is given by the formula:$T = 2\pi \sqrt{\frac{\ell}{g}}$From this relation,we can see that $T \propto \sqrt{\ell}$.If a clock is running fast,it means its time period $T$ is too small (it completes oscillations too quickly).To correct the time,we need to increase the time period $T$.Since $T$ is directly proportional to the square root of the length $\ell$,increasing the length $\ell$ will increase the time period $T$.The time period is independent of the mass of the bob and the amplitude of oscillation (for small angles).

$A$ pendulum clock is running fast. To correct its time,we should

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