$A$ disc of mass $m$ and radius $r$ rolls down an inclined plane of height $h$. When it reaches the bottom of the plane,its rotational kinetic energy is ($g=$ acceleration due to gravity).

  • A
    $\frac{mgh}{3}$
  • B
    $\frac{mgh}{6}$
  • C
    $\frac{mgh}{2}$
  • D
    $\frac{mgh}{4}$

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Similar Questions

Suppose a body of mass $M$ and radius $R$ is allowed to roll on an inclined plane without slipping from its topmost point $A$ at a height $h$. The velocity acquired by the body,as it reaches the bottom of the inclined plane,is given by $\beta = 1 + \frac{I}{MR^2}$. Find the expression for the velocity $v$.

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The speed of a homogeneous solid sphere after rolling down an inclined plane of vertical height $h$,from rest without sliding,is

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