(A) The initial moment of inertia of the ring about the transverse axis is $I = M R^2$. The initial angular momentum is $L_i = I \omega = M R^2 \omega

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) The initial moment of inertia of the ring about the transverse axis is $I = M R^2$. The initial angular momentum is $L_i = I \omega = M R^2 \omega$.When two objects of mass $m$ are attached to the opposite ends of a diameter,the new moment of inertia becomes $I' = M R^2 + m R^2 + m R^2 = (M + 2m) R^2$.Since no external torque acts on the system,the angular momentum is conserved,so $L_i = L_f$.$M R^2 \omega = (M + 2m) R^2 \omega'$$\omega' = \frac{M R^2 \omega}{(M + 2m) R^2} = \frac{M \omega}{M + 2m}$.

Class 11 Physics System of Particles and Rotational Motion Conservation of angular momentum (combined translation and rotational motion)

Medium

$A$ thin circular ring of mass $M$ and radius $R$ is rotating about a transverse axis passing through its centre with constant angular velocity $\omega$. Two objects each of mass $m$ are attached gently to the opposite ends of a diameter of the ring. What is the new angular velocity?

MHT CET 2020 All MHT CET

A
$\frac{M \omega}{M+2 m}$
B
$\frac{M \omega}{M+m}$
C
$\frac{(M+2 m) \omega}{M}$
D
$\frac{(M-2 m) \omega}{M+2 m}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

System of Particles and Rotational Motion

Subtopic

Conservation of angular momentum (combined translation and rotational motion)

Previous Year

MHT CET 2020 Paper All MHT CET years →

$A$ thin uniform rod of mass $M$ and length $L$ is rotating about a perpendicular axis passing through its centre with a constant angular velocity $\omega$. Two objects,each of mass $\frac{M}{3}$,are attached gently to the two ends of the rod. The rod will now rotate with an angular velocity of

MediumNEET 2017

View Solution

$A$ thin uniform circular disc of mass $M$ and radius $R$ is rotating in a horizontal plane about an axis passing through its centre and perpendicular to its plane with an angular velocity $\omega$. Another disc of same dimension but of mass $M/4$ is placed gently on the first disc coaxially. The angular velocity of the system now is

MediumIIT 1986

View Solution

$A$ thin uniform circular disc of mass $M$ and radius $R$ is rotating with angular velocity $\omega$ in a horizontal plane about an axis passing through its centre and perpendicular to its plane. Another disc of the same radius but of mass $\frac{M}{3}$ is placed gently on the first disc co-axially. The new angular velocity will be:

DifficultMHT CET 2024

View Solution

When a dancer pulls their arms inward while spinning on ice,they spin faster. This is due to:

Easy

View Solution

$A$ thin ring of mass $M$ and radius $R$ is rotating with an angular velocity $\omega$ about an axis passing through its center and perpendicular to its plane. If $4$ point masses each of mass $m$ are placed gently at the opposite ends of two mutually perpendicular diameters,what will be the new angular velocity of the system?

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ thin circular ring of mass $M$ and radius $R$ is rotating about a transverse axis passing through its centre with constant angular velocity $\omega$. Two objects each of mass $m$ are attached gently to the opposite ends of a diameter of the ring. What is the new angular velocity?

Similar Questions

$A$ thin uniform rod of mass $M$ and length $L$ is rotating about a perpendicular axis passing through its centre with a constant angular velocity $\omega$. Two objects,each of mass $\frac{M}{3}$,are attached gently to the two ends of the rod. The rod will now rotate with an angular velocity of

When a dancer pulls their arms inward while spinning on ice,they spin faster. This is due to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module