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(B) The number of photoelectrons emitted per second is directly proportional to the intensity of the incident light.For a point source of light,the in

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number of electrons emitted is a quarter of the initial number

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(B) The number of photoelectrons emitted per second is directly proportional to the intensity of the incident light.For a point source of light,the intensity $I$ follows the inverse square law: $I \propto \frac{1}{d^2}$,where $d$ is the distance from the source.When the distance is doubled $(d' = 2d)$,the new intensity $I'$ becomes $I' = \frac{I}{2^2} = \frac{I}{4}$.Since the number of photoelectrons emitted is directly proportional to the intensity,the number of photoelectrons emitted becomes one-fourth of the initial number.The energy of each emitted electron depends on the frequency of the incident light,not on its intensity. Therefore,the energy of each emitted electron remains unchanged.

$A$ photoelectric cell is illuminated by a point source of light $1 \ m$ away. When the source is shifted to $2 \ m$,then:

Similar Questions

The time taken by a photoelectron to come out after the photon strikes is approximately

If the intensity of incident light is increased in $PEE$,then which of the following is true?

The curves $(a), (b), (c)$ and $(d)$ show the variation between the applied potential difference $(V)$ and the photoelectric current $(i)$,at two different intensities of light $(I_1 > I_2)$. In which figure is the correct variation shown?

Which of the following phenomena is not explained by the wave nature of light?
$(A)$ Reflection
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Choose the most appropriate answer from the options given below:

Which graph represents the relationship between the intensity of incident light on a metal plate and the resulting photoelectric current?

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