$A$ lead bullet moving with velocity '$v$' strikes a wall and stops. If $50\%$ of its energy is converted into heat,then the increase in temperature is ($s =$ specific heat of lead,$J =$ mechanical equivalent of heat).

  • A
    $\frac{v^2 s}{2 J}$
  • B
    $\frac{v^2}{4 sJ}$
  • C
    $\frac{v^2 s}{J}$
  • D
    $\frac{2 v^2}{Js}$

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