A diffraction pattern is obtained using a bea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The width of the diffraction bands (or the distance between successive minima/maxima) is given by the formula $\beta = \frac{\lambda D}{a}$.From t

Vedclass · Accepted Answer

diffraction bands become narrow and crowded together.

Vedclass · Answer

(B) The width of the diffraction bands (or the distance between successive minima/maxima) is given by the formula $\beta = \frac{\lambda D}{a}$.From this relation,we can see that the band width $\beta$ is directly proportional to the wavelength $\lambda$ of the light used,i.e.,$\beta \propto \lambda$.We know that the wavelength of blue light is smaller than the wavelength of red light,i.e.,$\lambda_{	ext{blue}} Since $\lambda$ decreases,the band width $\beta$ also decreases.Therefore,the diffraction bands become narrow and crowded together.

$A$ diffraction pattern is obtained using a beam of red light. If red light is replaced by blue light,then:

Similar Questions

$A$ circular disc is placed in front of a narrow source. When the point of observation is $2 \, m$ from the disc,it covers the first $HPZ$. The intensity at this point is $I$. When the point of observation is $25 \, cm$ from the disc,the intensity will be:

Light is incident normally on a diffraction grating through which the first order diffraction is seen at $32^\circ$. The second order diffraction will be seen at

Assertion: The clouds in the sky generally appear to be whitish.
Reason: Diffraction due to clouds is efficient in equal measure at all wavelengths.

The diffraction of light starts from an obstacle (edge). It depends on ...

If $\lambda = 6000 \, \mathring{A}$ and $a = 18 \times 10^{-5} \, \text{cm}$,find the angular width of the central maximum in degrees $(^\circ)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module