(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{a}$,where $\lambda

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decreases with increase of slit width.

(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{a}$,where $\lambda$ is the wavelength of the light and $a$ is the width of the slit.From this relation,it is clear that the angular width $\theta$ is inversely proportional to the slit width $a$,i.e.,$\theta \propto \frac{1}{a}$.Therefore,as the slit width $a$ increases,the angular width of the central maximum decreases.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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A
increases with increase of slit width.
B
decreases with increase of slit width.
C
decreases with decrease of slit width.
D
may increase or decrease with decrease of slit width.

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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$A$ screen is placed at a certain distance from a narrow slit,which is illuminated by a parallel beam of monochromatic light. What will you observe if you scan the screen with the help of a microscope?

"The person standing behind the open door inside the room can hear the voice of the person standing on the other side of the door but they cannot see each other". Give an experiment based on the diffraction for this statement.

$A$ parallel beam of monochromatic light of wavelength $5 \times 10^{-7} \ m$ is incident normally on a single narrow slit of width $10^{-3} \ mm$. At what angle of diffraction is the first minima observed?

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