A sound wave of frequency 160 ,Hz has a veloc | vedclass

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(A) Given: Frequency $f = 160 \,Hz$, Velocity $v = 320 \,m/s$. First, calculate the wavelength $\lambda$ using the formula $\lambda = v/f$: $\lambda =

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$50$

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(A) Given: Frequency $f = 160 \,Hz$, Velocity $v = 320 \,m/s$. First, calculate the wavelength $\lambda$ using the formula $\lambda = v/f$: $\lambda = 320 / 160 = 2 \,m = 200 \,cm$. The relationship between phase difference $\phi$ and path difference $x$ is given by $\phi = \frac{2\pi x}{\lambda}$. Given phase difference $\phi = 90^{\circ} = \pi/2$ radians. Substituting the values: $\frac{\pi}{2} = \frac{2\pi x}{200}$. Solving for $x$: $x = \frac{\pi}{2} \cdot \frac{200}{2\pi} = \frac{200}{4} = 50 \,cm$.

$A$ sound wave of frequency $160 \,Hz$ has a velocity of $320 \,m/s$. When it travels through air, the particles having a phase difference of $90^{\circ}$ are separated by a distance of: (in $cm$)

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