$A$ string of mass $M$ is under a tension $T$. The length of the string is $L$. $A$ transverse wave starts at one end of the string. The time required for the disturbance to reach the other end is

$A$ wire $PQ$ has length $4.8 \ m$ and mass $0.06 \ kg$. Another wire $QR$ has length $2.56 \ m$ and mass $0.2 \ kg$. Both wires have the same radii and are joined as a single wire. This wire is under a tension of $80 \ N$. $A$ wave pulse of amplitude $3.5 \ cm$ is sent along the wire $PQ$ from end $P$. The time taken by the wave to reach the other end of the single wire is (No power is dissipated during propagation). (in $s$)

$A$ wire is under tension of $2 \text{ kg wt}$ and a wave is travelling through it with some speed. Tension in the wire is so increased that the wave travels through it with thrice the original speed. The increase in tension is (in kg wt)

$A$ string $1\,m$ long is driven by a $300\,Hz$ vibrator attached to its end. The string vibrates in three segments. The speed of transverse waves in the string is equal to ..... $m/s$.

$A$ rope of length $L$ and mass $M$ hangs freely from the ceiling. If the time taken by a transverse wave to travel from the bottom to the top of the rope is $T$,then the time taken to cover the first half length is:

$A$ composite string is made up by joining two strings of different mass per unit length,$\mu$ and $4\mu$. The composite string is under the same tension $T$. $A$ transverse wave pulse,$Y = (6 \text{ mm}) \sin(5t + 40x)$,where $t$ is in seconds and $x$ is in meters,is sent along the lighter string towards the joint. The joint is at $x = 0$. The equation of the wave pulse reflected from the joint is: