A pipe open at both ends of length 1.5 m is | vedclass

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(D) The speed of sound $v = 330 \ m/s$ and frequency $f = 330 \ Hz$. The wavelength $\lambda = v/f = 330/330 = 1 \ m$.When one end of an open pipe is

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$0.25$

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(D) The speed of sound $v = 330 \ m/s$ and frequency $f = 330 \ Hz$. The wavelength $\lambda = v/f = 330/330 = 1 \ m$.When one end of an open pipe is dipped in water,it acts as a pipe closed at one end.The length of the air column is $L' = L - x$,where $L = 1.5 \ m$ is the total length and $x$ is the length immersed.For a pipe closed at one end,the frequencies of harmonics are given by $f_n = (2n-1) \frac{v}{4L'}$,where $n=1$ is the fundamental,$n=2$ is the $1^{	ext{st}}$ overtone,and $n=3$ is the $2^{	ext{nd}}$ overtone.For the $2^{	ext{nd}}$ overtone,$n=3$,so $f_3 = 5 \frac{v}{4L'}$.Given $f_3 = 330 \ Hz$,we have $330 = 5 	imes \frac{330}{4L'}$.This simplifies to $1 = \frac{5}{4L'}$,which gives $4L' = 5$,or $L' = 1.25 \ m$.Since $L' = L - x$,we have $1.25 = 1.5 - x$.Therefore,$x = 1.5 - 1.25 = 0.25 \ m$.

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