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(D) For a cylindrical tube open at both ends with length $L$,the fundamental frequency is given by $f = \frac{v}{2L}$,where $v$ is the speed of sound

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$\frac{3f}{4}$

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(D) For a cylindrical tube open at both ends with length $L$,the fundamental frequency is given by $f = \frac{v}{2L}$,where $v$ is the speed of sound in air.When the tube is dipped vertically into water such that one-third of its length is submerged,the length of the air column becomes $L' = L - \frac{L}{3} = \frac{2L}{3}$.The tube now acts as a pipe closed at one end (the water surface) and open at the other.For a pipe closed at one end,the fundamental frequency is $f' = \frac{v}{4L'}$.Substituting $L' = \frac{2L}{3}$,we get $f' = \frac{v}{4(2L/3)} = \frac{3v}{8L}$.Since $f = \frac{v}{2L}$,we can write $f' = \frac{3}{4} 	imes \frac{v}{2L} = \frac{3}{4}f$.

$A$ cylindrical tube open at both ends has a fundamental frequency $f$ in air. When the tube is dipped vertically in water so that one-third part of the tube is in water,the fundamental frequency of the air column becomes (neglect end correction).

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