R^{prime}-X xrightarrow{Na / text{ether}} 2,3 | vedclass

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Question

(D) The reaction given is the Wurtz reaction,where an alkyl halide reacts with sodium in the presence of dry ether to form a symmetric alkane.$2R^{\pr

Vedclass · Accepted Answer

$(CH_3)_2CH-$

Vedclass · Answer

(D) The reaction given is the Wurtz reaction,where an alkyl halide reacts with sodium in the presence of dry ether to form a symmetric alkane.$2R^{\prime}-X + 2Na \xrightarrow{	ext{ether}} R^{\prime}-R^{\prime} + 2NaX$Given the product is $2,3-	ext{dimethylbutane}$,which has the structure $(CH_3)_2CH-CH(CH_3)_2$.This indicates that the alkyl group $R^{\prime}$ must be an isopropyl group,$(CH_3)_2CH-$.Therefore,$R^{\prime}-X$ is isopropyl halide,$(CH_3)_2CH-X$.

$R^{\prime}-X \xrightarrow{Na / \text{ether}} 2,3-\text{dimethylbutane}$. Identify $R^{\prime}$.

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