(A) For a first order reaction,the half-life $(t_{1/2})$ is given by the formula: $t_{1/2} = \frac{0.693}{k}$.Given $k = 5.5 \times 10^{-14} \ s^{-1}$

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(A) For a first order reaction,the half-life $(t_{1/2})$ is given by the formula: $t_{1/2} = \frac{0.693}{k}$.Given $k = 5.5 \times 10^{-14} \ s^{-1}$.Substituting the value of $k$ in the formula:$t_{1/2} = \frac{0.693}{5.5 \times 10^{-14}} \ s$.$t_{1/2} = 0.126 \times 10^{14} \ s$.$t_{1/2} = 1.26 \times 10^{13} \ s$.

Class 12 Chemistry Chemical Kinetics First Order reaction

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$A$ first order reaction is found to have a rate constant,$k = 5.5 \times 10^{-14} \ s^{-1}$. The half life of reaction is . . . . . . .

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A
$1.26 \times 10^{13} \ s$
B
$1.26 \times 10^{14} \ s$
C
$6.93 \times 10^{14} \ s$
D
$12.6 \times 10^{15} \ s$

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Which one of the following plots is correct for a first order reaction?

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Medium

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For the first order reaction $A \rightarrow B$,the half-life is $30 \ min$. The time taken for $75 \%$ completion of the reaction is $..... \ min$. (Nearest integer)
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DifficultJEE MAIN 2023

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$A$ first order reaction is found to have a rate constant,$k = 5.5 \times 10^{-14} \ s^{-1}$. The half life of reaction is . . . . . . .

Similar Questions

The rate constant of a first order reaction is $1.15 \times 10^{-3} \ s^{-1}$. How long will $5 \ g$ of reactant take to reduce to $3 \ g$ (in $s$)?

Which one of the following plots is correct for a first order reaction?

$A_{(g)} \rightarrow 2B_{(g)}$. Initially,$2 \ mol$ of $A$ are taken in a $5 \ L$ vessel. After $20 \ min$,$[A]_t = \frac{[B]_t}{2}$. Find the half-life time of $A$ in the first-order reaction in $\min$.

For the first order reaction $A \rightarrow B$,the half-life is $30 \ min$. The time taken for $75 \%$ completion of the reaction is $..... \ min$. (Nearest integer)Given: $\log 2 = 0.3010, \log 3 = 0.4771, \log 5 = 0.6989$

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For the first order reaction $A \rightarrow B$,the half-life is $30 \ min$. The time taken for $75 \%$ completion of the reaction is $..... \ min$. (Nearest integer)
Given: $\log 2 = 0.3010, \log 3 = 0.4771, \log 5 = 0.6989$