$\left|\begin{array}{lll}10 & 11 & 12 \\ 11 & 12 & 13 \\ 12 & 13 & 14\end{array}\right|=$ . . . . . . .

  • A
    $-2(10!\cdot 11!\cdot 12!)$
  • B
    $0$
  • C
    $2(10!\cdot 13!)$
  • D
    $2(10!\cdot 12!\cdot 13!)$

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