$A$ point charge causes an electrical flux of $-1.0 \times 10^3 \ Nm^2 \ C^{-1}$ to pass through a spherical Gaussian surface of $10 \ cm$ radius centered on the charge. If the radius of the Gaussian surface were $3$ times,how much flux would pass through the surface?

Give a reason: 'If the net flux associated with a closed surface is zero,then the net charge enclosed by that surface is zero.'

The electric flux passing through the cube for the given arrangement of charges placed at the corners of the cube (as shown in the figure) is:

If the electric flux entering and leaving an enclosed surface respectively is $\phi_1$ and $\phi_2$, the electric charge inside the surface will be:

The figure shows some of the electric field lines corresponding to an electric field. The figure suggests

An infinitely long uniform line charge distribution of charge per unit length $\lambda$ lies parallel to the $y$-axis in the $y-z$ plane at $z=\frac{\sqrt{3}}{2} a$ (see figure). If the magnitude of the flux of the electric field through the rectangular surface $A B C D$ lying in the $x-y$ plane with its center at the origin is $\frac{\lambda L }{ n \varepsilon_0}$ (where $\varepsilon_0$ is the permittivity of free space),then the value of $n$ is