(A) The induced electromotive force $(\varepsilon)$ across a rotating conducting spoke in a magnetic field is given by the formula: $\varepsilon = \fr

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(A) The induced electromotive force $(\varepsilon)$ across a rotating conducting spoke in a magnetic field is given by the formula: $\varepsilon = \frac{1}{2} B \omega R^2$.Given values are:Magnetic field $(B)$ = $0.2 \, T$Angular velocity $(\omega)$ = $10 \, rad \, s^{-1}$Radius $(R)$ = $2 \, m$Substituting these values into the formula:$\varepsilon = \frac{1}{2} \times 0.2 \times 10 \times (2)^2$$\varepsilon = 0.1 \times 10 \times 4$$\varepsilon = 4 \, V$The number of spokes does not affect the potential difference between the rim and the center, as they are connected in parallel.

Class 12 Physics Electromagnetic Induction Motional EMI (Induced Parameter)

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$A$ wheel of radius $2 \, m$ having $8$ conducting concentric spokes is rotating about its geometrical axis with an angular velocity of $10 \, rad \, s^{-1}$ in a uniform magnetic field of $0.2 \, T$ perpendicular to its plane. The value of induced emf between the rim of the wheel and the centre is . . . . . . $V$.

GUJCET 2019 All GUJCET

A
$4$
B
$2$
C
$6$
D
$8$

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Electromagnetic Induction

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Motional EMI (Induced Parameter)

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$A$ rectangular loop has a sliding connector $PQ$ of length $l$ and resistance $R \ \Omega$ and it is moving with a speed $v$ as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents $I_1, I_2$ and $I$ are:

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In the given arrangement,a loop of width $b$ is moved with constant velocity $v$ through a uniform magnetic field $B$ restricted to a region of width $a$ (where $b > a$). The total time for which an $emf$ is induced in the circuit is:

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$A$ coil of $N$ turns and mean cross-sectional area $A$ is rotating with uniform angular velocity $\omega$ about an axis at right angle to a uniform magnetic field $B$. The induced e.m.f. $E$ in the coil will be

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$A$ long metal rod of length $L$ completes the circuit as shown. The area of the circuit is perpendicular to the magnetic field $B$. The total resistance of the circuit is $R$. The force needed to move the rod in the direction as shown with a constant speed $V$ is:

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$A$ metallic rod of length $l$ is tied to a string of length $2l$ and made to rotate with angular speed $\omega$ on a horizontal table with one end of the string fixed. If there is a vertical magnetic field $B$ in the region,the $e.m.f.$ induced across the ends of the rod is

MediumJEE MAIN 2013

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$A$ rectangular loop has a sliding connector $PQ$ of length $l$ and resistance $R \ \Omega$ and it is moving with a speed $v$ as shown. The set-up is placed in a uniform magnetic field going into the plane of the paper. The three currents $I_1, I_2$ and $I$ are:

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