left( frac{sin 2A}{1 + cos 2A} right) left( f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We are given the expression: $\left( \frac{\sin 2A}{1 + \cos 2A} \right) \left( \frac{\cos A}{1 + \cos A} \right)$Using the double angle identitie

Vedclass · Accepted Answer

$	an \frac{A}{2}$

Vedclass · Answer

(A) We are given the expression: $\left( \frac{\sin 2A}{1 + \cos 2A} ight) \left( \frac{\cos A}{1 + \cos A} ight)$Using the double angle identities $\sin 2A = 2 \sin A \cos A$ and $1 + \cos 2A = 2 \cos^2 A$,we get:$= \left( \frac{2 \sin A \cos A}{2 \cos^2 A} ight) \left( \frac{\cos A}{1 + \cos A} ight)$$= \left( \frac{\sin A}{\cos A} ight) \left( \frac{\cos A}{1 + \cos A} ight)$$= \frac{\sin A}{1 + \cos A}$Using the half-angle identity $\sin A = 2 \sin \frac{A}{2} \cos \frac{A}{2}$ and $1 + \cos A = 2 \cos^2 \frac{A}{2}$:$= \frac{2 \sin \frac{A}{2} \cos \frac{A}{2}}{2 \cos^2 \frac{A}{2}}$$= \frac{\sin \frac{A}{2}}{\cos \frac{A}{2}} = 	an \frac{A}{2}$.

$\left( \frac{\sin 2A}{1 + \cos 2A} \right) \left( \frac{\cos A}{1 + \cos A} \right) = $

Similar Questions

If $\tan x + \tan \left(x + \frac{\pi}{3}\right) + \tan \left(x + \frac{2\pi}{3}\right) = 3$,then $\tan 3x$ is equal to

$\frac{1-\sin \theta+\cos \theta}{1-\sin \theta-\cos \theta} = $

If $\sin(\frac{\pi}{18}) \sin(\frac{5\pi}{18}) \sin(\frac{7\pi}{18}) = K$, then the value of $\sin(\frac{10K\pi}{3})$ is :

Prove that $\sin 2x + 2 \sin 4x + \sin 6x = 4 \cos^2 x \sin 4x$.

If $\tan \alpha = \frac{-12}{5}$,$\cot \beta = \frac{7}{24}$,$\alpha$ does not belong to the second quadrant,and $\beta$ does not belong to the first quadrant,then $\sqrt{13} \sin \frac{\alpha}{2} + \cos \frac{\beta}{2} + \tan \frac{\alpha}{2} \cot \frac{\beta}{2} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module