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Question

(A) The relationship between speed of light $(c)$, frequency $(
u)$, and wavelength $(\lambda)$ is given by $c = 
u \lambda$. Therefore, the wavelen

Vedclass · Accepted Answer

$25 	ext{ m}$ to $50 	ext{ m}$

Vedclass · Answer

(A) The relationship between speed of light $(c)$, frequency $(
u)$, and wavelength $(\lambda)$ is given by $c = 
u \lambda$. Therefore, the wavelength is $\lambda = \frac{c}{
u}$. For the lower frequency limit $
u_1 = 6 	ext{ MHz} = 6 	imes 10^6 	ext{ Hz}$, the wavelength is: $\lambda_1 = \frac{3 	imes 10^8}{6 	imes 10^6} = \frac{300}{6} = 50 	ext{ m}$. For the upper frequency limit $
u_2 = 12 	ext{ MHz} = 12 	imes 10^6 	ext{ Hz}$, the wavelength is: $\lambda_2 = \frac{3 	imes 10^8}{12 	imes 10^6} = \frac{300}{12} = 25 	ext{ m}$. Thus, the corresponding wavelength band is $25 	ext{ m}$ to $50 	ext{ m}$.

$A$ radio can tune into any station in the $6 \text{ MHz}$ to $12 \text{ MHz}$ band. What is the corresponding wavelength band? ( $c = 3 \times 10^{8} \text{ m/s}$ )

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