$A$ glass prism having a refractive index $\mu$ is placed in air. If the angle of minimum deviation of the prism is equal to the angle of the prism,what is the value of the angle of the prism?

$A$ ray of light is incident at an angle '$i$' on one face of a prism of small angle '$A$' and emerges normally from the other surface. If '$\mu$' is the refractive index of the material of the prism,then the angle of incidence is:

$A$ light ray is incident upon a prism in minimum deviation position and suffers a deviation of $34^o$. If the shaded half of the prism is removed,the ray will

The exit surface of a prism with refractive index $n$ is coated with a material having refractive index $\frac{n}{2}$. When this prism is set for minimum angle of deviation, it exactly meets the condition of the critical angle. The prism angle is . . . . . . (in $^{\circ}$)

$A$ ray of light is incident on one face of an equilateral glass prism having refractive index $\sqrt{2}$. It produces the emergent ray which just grazes along the adjacent face. The value of angle of incidence is

The angle of minimum deviation produced by a thin prism in air is $\delta_1$. What will be the minimum deviation $(\delta_2)$ if the prism is immersed in liquid? Given: refractive index of glass with respect to air $^a n_g = \frac{3}{2}$ and refractive index of liquid with respect to air $^a n_l = \frac{4}{3}$.