3.0 g ethanoic acid in 50 g benzene has . | vedclass

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(B) The molar mass of ethanoic acid $(CH_3COOH)$ is $(2 	imes 12) + (4 	imes 1) + (2 	imes 16) = 24 + 4 + 32 = 60 \ g/mol$. Number of moles of etha

Vedclass · Accepted Answer

$1.0$

Vedclass · Answer

(B) The molar mass of ethanoic acid $(CH_3COOH)$ is $(2 	imes 12) + (4 	imes 1) + (2 	imes 16) = 24 + 4 + 32 = 60 \ g/mol$. Number of moles of ethanoic acid = $\frac{	ext{mass}}{	ext{molar mass}} = \frac{3.0 \ g}{60 \ g/mol} = 0.05 \ mol$. Mass of solvent (benzene) = $50 \ g = 0.05 \ kg$. Molality $(m)$ = $\frac{	ext{moles of solute}}{	ext{mass of solvent in kg}} = \frac{0.05 \ mol}{0.05 \ kg} = 1.0 \ mol/kg$. Therefore,the correct option is $B$.

$3.0 \ g$ ethanoic acid in $50 \ g$ benzene has . . . . . . molality. (Atomic weights: $H=1, C=12, O=16$).

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