$A$ circular coil of radius $10 \text{ cm}$ and $100$ turns carries a current of $1 \text{ A}$. What is the magnetic moment of the coil?

$A$ circular loop has a radius of $5\, cm$ and it is carrying a current of $0.1\, A$. Its magnetic moment is

Two circular concentric loops of radii $r_1 = 20\,cm$ and $r_2 = 30\,cm$ are placed in the $X, Y-$ plane as shown in the figure. $A$ current $I = 7\,A$ is flowing through them in opposite directions. The magnetic moment of this loop system is

$A$ conducting ring of radius $R$ and one turn is formed from a conducting wire of length $L$ and on passing current $I$ the obtained magnetic dipole moment is $m$. If this wire is then converted to a ring of two turns and on passing electric current $I$,the new magnetic dipole moment obtained is . . . . . . .

$A$ ring of radius $R$,made of an insulating material,carries a charge $Q$ uniformly distributed on it. If the ring rotates about the axis passing through its centre and normal to the plane of the ring with a constant angular speed $\omega$,then the magnitude of the magnetic moment of the ring is:

In the given diagram,a rod is rotating with angular velocity $\omega$. The mass of this rod is $m$,the charge is $q$,and the length is $l$. Find the magnetic moment of this rod.